Question Number 81942 by TawaTawa last updated on 16/Feb/20
Answered by TANMAY PANACEA last updated on 16/Feb/20
$${for}\:{bank}\:{p}\:{interest}=\frac{\mathrm{3000}×\mathrm{1}×{x}}{\mathrm{100}}=\mathrm{30}{x} \\ $$$${for}\:{bank}\:{Q}\:{interst}=\frac{\mathrm{2000}×\mathrm{1}×{y}}{\mathrm{100}}=\mathrm{20}{y} \\ $$$${as}\:{per}\:{second}\:{condition} \\ $$$${interest}\:{in}\:{bank}\:{p}=\frac{\mathrm{2000}×\mathrm{1}×{x}}{\mathrm{100}}=\mathrm{20}{x} \\ $$$${interst}\:{in}\:{bank}\:{Q}\:\:=\frac{\mathrm{3000}×\mathrm{1}×{y}}{\mathrm{100}}=\mathrm{30}{y} \\ $$$$\left(\mathrm{20}{x}+\mathrm{30}{y}\right)−\left(\mathrm{30}{x}+\mathrm{20}{y}\right)=\mathrm{20} \\ $$$$\mathrm{10}{y}−\mathrm{10}{x}=\mathrm{20} \\ $$$${y}−{x}=\mathrm{2} \\ $$$${data}\:{in}\:{sufficient} \\ $$
Commented by TawaTawa last updated on 16/Feb/20
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$