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Question-81942




Question Number 81942 by TawaTawa last updated on 16/Feb/20
Answered by TANMAY PANACEA last updated on 16/Feb/20
for bank p interest=((3000×1×x)/(100))=30x  for bank Q interst=((2000×1×y)/(100))=20y  as per second condition  interest in bank p=((2000×1×x)/(100))=20x  interst in bank Q  =((3000×1×y)/(100))=30y  (20x+30y)−(30x+20y)=20  10y−10x=20  y−x=2  data in sufficient
$${for}\:{bank}\:{p}\:{interest}=\frac{\mathrm{3000}×\mathrm{1}×{x}}{\mathrm{100}}=\mathrm{30}{x} \\ $$$${for}\:{bank}\:{Q}\:{interst}=\frac{\mathrm{2000}×\mathrm{1}×{y}}{\mathrm{100}}=\mathrm{20}{y} \\ $$$${as}\:{per}\:{second}\:{condition} \\ $$$${interest}\:{in}\:{bank}\:{p}=\frac{\mathrm{2000}×\mathrm{1}×{x}}{\mathrm{100}}=\mathrm{20}{x} \\ $$$${interst}\:{in}\:{bank}\:{Q}\:\:=\frac{\mathrm{3000}×\mathrm{1}×{y}}{\mathrm{100}}=\mathrm{30}{y} \\ $$$$\left(\mathrm{20}{x}+\mathrm{30}{y}\right)−\left(\mathrm{30}{x}+\mathrm{20}{y}\right)=\mathrm{20} \\ $$$$\mathrm{10}{y}−\mathrm{10}{x}=\mathrm{20} \\ $$$${y}−{x}=\mathrm{2} \\ $$$${data}\:{in}\:{sufficient} \\ $$
Commented by TawaTawa last updated on 16/Feb/20
God bless you sir.
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$

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