Question Number 83481 by gny last updated on 02/Mar/20
Commented by gny last updated on 02/Mar/20
$${sir}\:{could}\:{you}\:{help}\:{me}\:\:\:\:\:\:\:\:\:\:\:{Find}\:\:\alpha+\beta \\ $$
Commented by mathmax by abdo last updated on 02/Mar/20
$$\alpha+\mathrm{10}\:+\beta+\mathrm{20}\:=\mathrm{180}\:\Rightarrow\alpha+\beta\:=\mathrm{180}−\mathrm{30}\:=\mathrm{150}^{{o}} \\ $$
Commented by gny last updated on 03/Mar/20
$${thank}\:{you}\:{sir} \\ $$
Answered by Rio Michael last updated on 04/Mar/20
$$\left(\beta\:+\:\mathrm{20}\right)°+\left(\:\alpha\:+\:\mathrm{10}\right)°\:=\:\mathrm{180}° \\ $$$$\Rightarrow\:\alpha\:+\:\beta\:=\:\mathrm{180}\:°−\:\mathrm{20}°\:−\:\mathrm{10}\:° \\ $$$$\:\:\:\:\:\:\alpha\:+\:\beta\:=\:\mathrm{150}° \\ $$