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Question-83524




Question Number 83524 by liki last updated on 03/Mar/20
Commented by liki last updated on 03/Mar/20
...help me plz qns no. 5,7 and 9
helpmeplzqnsno.5,7and9
Commented by liki last updated on 03/Mar/20
...plz help me  .....
plzhelpme..
Answered by Kunal12588 last updated on 03/Mar/20
Commented by Kunal12588 last updated on 03/Mar/20
(dr_2 /dt)=1 cm/s  ,  (dr_1 /dt)=2 cm/s  A_(shaded) =πr_2 ^2 −πr_1 ^2   ⇒A_(shaded) =π(r_2 ^2 −r_1 ^2 )  ⇒(dA/dt)=2π(r_2 ×(dr_1 /dt)−r_1 ×(dr_2 /dt))  ⇒(dA/dt)=2π(r_2 (1)−r_1 (2))  ⇒(dA/dt)=2π(r_2 −2r_1 )  when r_1 =8 cm, r_2 =12 cm  (dA/dt)=2π(12−16)  (dA/dt)=−8π cm/s
dr2dt=1cm/s,dr1dt=2cm/sAshaded=πr22πr12Ashaded=π(r22r12)dAdt=2π(r2×dr1dtr1×dr2dt)dAdt=2π(r2(1)r1(2))dAdt=2π(r22r1)whenr1=8cm,r2=12cmdAdt=2π(1216)dAdt=8πcm/s
Answered by Kunal12588 last updated on 03/Mar/20
Commented by Kunal12588 last updated on 03/Mar/20
(r/h)=((12)/(18))  ⇒r=((2h)/3)  V=(1/3)πr^2 h  ⇒V=(1/3)π×(4/9)h^3   ⇒V=(4/(27))πh^3   ⇒(dV/dh)=(4/9)πh^2 ×(dh/dt)  ⇒(dV/dh)=(4/9)π×36×(dh/dt)  ⇒2=16π(dh/dt)  ⇒(dh/dt)=(1/(8π))cm/s
rh=1218r=2h3V=13πr2hV=13π×49h3V=427πh3dVdh=49πh2×dhdtdVdh=49π×36×dhdt2=16πdhdtdhdt=18πcm/s

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