Question-83554

Question Number 83554 by Power last updated on 03/Mar/20

Answered by MJS last updated on 03/Mar/20

x^{4} + 4 x^{3} - 8 x + \frac{17}{5} = 0

let x = t - 1

t^{4} - 6 t^{2} + \frac{42}{5} = 0

t^{2} = 3 \pm \frac{\sqrt{15}}{5}

t = \pm \sqrt{3 \pm \frac{\sqrt{15}}{5}}

x = - 1 \pm \sqrt{3 \pm \frac{\sqrt{15}}{5}}

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