Question Number 84960 by jagoll last updated on 18/Mar/20
Answered by jagoll last updated on 18/Mar/20
Answered by mr W last updated on 18/Mar/20
$$\frac{{x}_{\mathrm{1}} }{\mathrm{4}}=\frac{{x}_{\mathrm{2}} +\mathrm{6}}{\mathrm{14}}\:\Rightarrow\:\mathrm{7}{x}_{\mathrm{1}} −\mathrm{2}{x}_{\mathrm{2}} =\mathrm{12}\:\:\:…\left({i}\right) \\ $$$$\frac{{x}_{\mathrm{1}} +\mathrm{4}}{\mathrm{14}}=\frac{{x}_{\mathrm{2}} }{\mathrm{6}}\:\Rightarrow\:\mathrm{3}{x}_{\mathrm{1}} −\mathrm{7}{x}_{\mathrm{2}} =−\mathrm{12}\:\:\:…\left({ii}\right) \\ $$$$\Rightarrow{x}_{\mathrm{1}} =\frac{\mathrm{108}}{\mathrm{43}},\:{x}_{\mathrm{2}} =\frac{\mathrm{120}}{\mathrm{43}} \\ $$$$\Rightarrow{x}={x}_{\mathrm{1}} +{x}_{\mathrm{2}} =\frac{\mathrm{228}}{\mathrm{43}} \\ $$
Commented by mr W last updated on 18/Mar/20
Commented by jagoll last updated on 18/Mar/20
$$\mathrm{waw}…\mathrm{amazing} \\ $$