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Question-84960




Question Number 84960 by jagoll last updated on 18/Mar/20
Answered by jagoll last updated on 18/Mar/20
Answered by mr W last updated on 18/Mar/20
(x_1 /4)=((x_2 +6)/(14)) ⇒ 7x_1 −2x_2 =12   ...(i)  ((x_1 +4)/(14))=(x_2 /6) ⇒ 3x_1 −7x_2 =−12   ...(ii)  ⇒x_1 =((108)/(43)), x_2 =((120)/(43))  ⇒x=x_1 +x_2 =((228)/(43))
$$\frac{{x}_{\mathrm{1}} }{\mathrm{4}}=\frac{{x}_{\mathrm{2}} +\mathrm{6}}{\mathrm{14}}\:\Rightarrow\:\mathrm{7}{x}_{\mathrm{1}} −\mathrm{2}{x}_{\mathrm{2}} =\mathrm{12}\:\:\:…\left({i}\right) \\ $$$$\frac{{x}_{\mathrm{1}} +\mathrm{4}}{\mathrm{14}}=\frac{{x}_{\mathrm{2}} }{\mathrm{6}}\:\Rightarrow\:\mathrm{3}{x}_{\mathrm{1}} −\mathrm{7}{x}_{\mathrm{2}} =−\mathrm{12}\:\:\:…\left({ii}\right) \\ $$$$\Rightarrow{x}_{\mathrm{1}} =\frac{\mathrm{108}}{\mathrm{43}},\:{x}_{\mathrm{2}} =\frac{\mathrm{120}}{\mathrm{43}} \\ $$$$\Rightarrow{x}={x}_{\mathrm{1}} +{x}_{\mathrm{2}} =\frac{\mathrm{228}}{\mathrm{43}} \\ $$
Commented by mr W last updated on 18/Mar/20
Commented by jagoll last updated on 18/Mar/20
waw...amazing
$$\mathrm{waw}…\mathrm{amazing} \\ $$

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