Question Number 85670 by TawaTawa1 last updated on 23/Mar/20
Commented by john santu last updated on 24/Mar/20
$$\mathrm{80}\:=\:\left(\mathrm{2}+{EF}\right)×\mathrm{10} \\ $$$${EF}\:=\:\mathrm{6}\:{cm}\: \\ $$$$ \\ $$
Commented by john santu last updated on 24/Mar/20
$$\Delta{AEF}\:{congruent}\:\Delta{BCD} \\ $$$${DC}\:=\:{FE}\:=\:\mathrm{6}\:{cm} \\ $$
Commented by TawaTawa1 last updated on 24/Mar/20
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$