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Question-85871

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Question Number 85871 by M±th+et£s last updated on 25/Mar/20
Commented by Rio Michael last updated on 25/Mar/20
all integers
allintegers
Commented by mr W last updated on 25/Mar/20
all integers except 1. x=1+δ f(x)=[1+d]^2 −[(1+d)^2 ] lim_(x→1^+ ) f(x)=lim_(δ→0) {[1+d]^2 −[(1+d)^2 ]}=1−1=0 x=1−δ f(x)=[1−d]^2 −[(1−d)^2 ] lim_(x→1^− ) f(x)=lim_(δ→0) {[1−d]^2 −[(1−d)^2 ]}=0−0=0 f(1)=1−1=0 lim_(x→1^− ) f(x)=lim_(x→1^+ ) f(x)=f(1) ⇒continuous at x=1
allintegersexcept1.x=1+δf(x)=[1+d]2−[(1+d)2]limx→1+f(x)=limδ→0{[1+d]2−[(1+d)2]}=1−1=0x=1−δf(x)=[1−d]2−[(1−d)2]limx→1−f(x)=limδ→0{[1−d]2−[(1−d)2]}=0−0=0f(1)=1−1=0limx→1−f(x)=limx→1+f(x)=f(1)⇒continuousatx=1
Commented by M±th+et£s last updated on 25/Mar/20
thank you so much sir
thankyousomuchsir

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