Question Number 86356 by MASANJAJ last updated on 28/Mar/20
Commented by MASANJAJ last updated on 28/Mar/20
$${please}\:{help}\:{me}\:{to}\:{find}\:{inqualities}\:{of}\: \\ $$$${this}\:{question} \\ $$
Answered by MJS last updated on 28/Mar/20
$$\mathrm{40}{x}+\mathrm{60}{y}\:=\:\mathrm{max} \\ $$$${x}+{y}=\mathrm{10}\:\Rightarrow\:{y}=\mathrm{10}−{x} \\ $$$${x}\geqslant\mathrm{2}\wedge{y}\geqslant\mathrm{2} \\ $$$${x}\geqslant\mathrm{2}\wedge\mathrm{10}−{x}\geqslant\mathrm{2}\:\Leftrightarrow\:\mathrm{2}\leqslant{x}\leqslant\mathrm{8} \\ $$$$\mathrm{40}{x}+\mathrm{60}\left(\mathrm{10}−{x}\right)=\mathrm{600}−\mathrm{20}{x} \\ $$$$\Rightarrow\:\mathrm{maximum}\:\mathrm{at}\:{x}=\mathrm{2}\wedge{y}=\mathrm{8} \\ $$
Commented by MASANJAJ last updated on 28/Mar/20
$${how}\:{about}\:\mathrm{150}{sh}\:{and}\:\mathrm{200}{sh} \\ $$
Commented by MJS last updated on 28/Mar/20
$$\mathrm{we}\:\mathrm{do}\:\mathrm{not}\:\mathrm{need}\:\mathrm{this}\:\mathrm{info} \\ $$$$\mathrm{there}'\mathrm{s}\:\mathrm{no}\:\mathrm{limitation}\:\mathrm{how}\:\mathrm{much}\:\mathrm{money}\:\mathrm{she} \\ $$$$\mathrm{can}\:\mathrm{spend} \\ $$