Question Number 86918 by gny last updated on 01/Apr/20
Commented by jagoll last updated on 01/Apr/20
$$\mathrm{what}\:\mathrm{is}\:\mathrm{question}? \\ $$
Commented by 21042009 last updated on 23/Apr/20
$${y}=\mathrm{cos}\:\frac{\mathrm{5}{x}}{\mathrm{6}} \\ $$$${y}'=−\frac{\mathrm{5}}{\mathrm{6}}\mathrm{sin}\:\frac{\mathrm{5}{x}}{\mathrm{6}} \\ $$