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Question-87671




Question Number 87671 by TawaTawa1 last updated on 05/Apr/20
Commented by TawaTawa1 last updated on 05/Apr/20
I got  10.5 m^(2 )   but am not sure.  Please help me check.
Igot10.5m2butamnotsure.Pleasehelpmecheck.
Commented by Tony Lin last updated on 05/Apr/20
7^2 ×((2π)/3)×(1/2)−7^2 ×((√3)/4)  =49((π/3)−((√3)/4))  ≈30(cm^2 )  =0.003(m^2 )  0.0049−0.003=0.0019(m^2 )
72×2π3×1272×34=49(π334)30(cm2)=0.003(m2)0.00490.003=0.0019(m2)
Commented by TawaTawa1 last updated on 05/Apr/20
God bless you sir
Godblessyousir
Answered by mr W last updated on 05/Apr/20
A_(shade) =7×7−2×((π×7^2 )/6)+((7^2 ×(√3))/4)  =49−((49π)/3)+((49(√3))/4)  ≈18.9 cm^2 =0.00189 m^2
Ashade=7×72×π×726+72×34=4949π3+493418.9cm2=0.00189m2
Commented by TawaTawa1 last updated on 05/Apr/20
God bless you sir
Godblessyousir
Commented by TawaTawa1 last updated on 05/Apr/20
Sir, have been trying to understand      −  2 × ((π × 7^2 )/6)  +  ((7^2  × (√3))/4)   But since i did not understand.  Please help me explain when you are chanced sir.  Please.
Sir,havebeentryingtounderstand2×π×726+72×34Butsinceididnotunderstand.Pleasehelpmeexplainwhenyouarechancedsir.Please.
Commented by mr W last updated on 05/Apr/20
Commented by mr W last updated on 05/Apr/20
Commented by mr W last updated on 05/Apr/20
A_1 =square=7×7  A_2 =sector=((circle)/6)=((π×7^2 )/6)  A_3 =equilateral triangle=(1/2)×7×(((√3)×7)/2)=((7^2 (√3))/4)  A_(shade) =A_1 −2A_2 +A_3   =7×7−2×((7^2 π)/6)+((7^2 (√3))/4)  =49−((49π)/3)+((49(√3))/4)
A1=square=7×7A2=sector=circle6=π×726A3=equilateraltriangle=12×7×3×72=7234Ashade=A12A2+A3=7×72×72π6+7234=4949π3+4934
Commented by TawaTawa1 last updated on 05/Apr/20
Hahaha.  Am happy.  I understand now,  God will be helping you too sir.
Hahaha.Amhappy.Iunderstandnow,Godwillbehelpingyoutoosir.

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