Question Number 87966 by M±th+et£s last updated on 07/Apr/20
Answered by ajfour last updated on 07/Apr/20
$${y}={kx}^{\mathrm{2}} \\ $$$$\mathrm{8}=\mathrm{4}{k}\:\:\Rightarrow\:\:{k}=\mathrm{2}\:\:\Rightarrow\:{y}=\mathrm{2}{x}^{\mathrm{2}} \\ $$$$\Rightarrow\:\:{x}^{\mathrm{2}} =\mathrm{4}\left(\frac{\mathrm{2}+{a}}{\mathrm{8}}\right){y}\:=\:\frac{{y}}{\mathrm{2}} \\ $$$$\Rightarrow\:\:{a}=\mathrm{2}\:. \\ $$
Commented by M±th+et£s last updated on 07/Apr/20
$${god}\:{bless}\:{you}\:{sir} \\ $$