Menu Close

Question-88021




Question Number 88021 by naka3546 last updated on 07/Apr/20
Commented by MJS last updated on 07/Apr/20
I get 4∨5... not sure how I got there...
Iget45notsurehowIgotthere
Commented by naka3546 last updated on 08/Apr/20
you′re  right , sir.
youreright,sir.
Answered by $@ty@m123 last updated on 08/Apr/20
p+q+r+s=9 {where p=(a/b) and so on  pq+qr+rs+sp=20  ⇒(p+r)(q+s)=20  Equation whose roots are p+r, q+s is  x^2 −9x+20=0  x=4,5
p+q+r+s=9{wherep=abandsoonpq+qr+rs+sp=20(p+r)(q+s)=20Equationwhoserootsarep+r,q+sisx29x+20=0x=4,5
Commented by Prithwish Sen 1 last updated on 08/Apr/20
I think it will be  (p+r)(q+s)=20
Ithinkitwillbe(p+r)(q+s)=20
Commented by $@ty@m123 last updated on 08/Apr/20
Thanks for correction.
Thanksforcorrection.

Leave a Reply

Your email address will not be published. Required fields are marked *