Question-88029 Tinku Tara June 4, 2023 Differentiation 0 Comments FacebookTweetPin Question Number 88029 by M±th+et£s last updated on 07/Apr/20 Answered by mind is power last updated on 08/Apr/20 −4sin2(4x)−8sin(4x)−9cos2(4x)+12cos(4x)−4+6sin(8x)=−(2sin(4x)−3cos(4x)+2)2f(x)=−(2sin(4x)−3cos(4x)+2)2+1+4−6cos(4x)+4sin(4x)2sin(4x)−3cos(4x)+2letY(x)=2sin(4x)−3cos(4x)+2g(y)=−Y+1Y+2g′(y)=−1−1y2y(x+π2)=y(x)2sin(4x)−3cos(4x)+2=0⇒13sin(4x−arcsin(213))+2=0hassolutionminandmaxdidntexiste Commented by M±th+et£s last updated on 08/Apr/20 godblessyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-88026Next Next post: find-0-1-sin-x-x-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.