Question Number 88936 by naka3546 last updated on 14/Apr/20
Answered by ajfour last updated on 14/Apr/20
$${let}\:\:\:{a}=\sqrt{\mathrm{196}−{c}^{\mathrm{2}} }\:\:\:\:{from}\:\mathrm{1}^{{st}} \\ $$$${b}^{\mathrm{2}} =\:\mathrm{2}{c}\sqrt{\mathrm{196}−{c}^{\mathrm{2}} }−\mathrm{27}\:\:\:{from}\:\mathrm{2}^{{nd}} \\ $$$${and}\:\:\:\:{b}^{\mathrm{2}} =\left({c}+\sqrt{\mathrm{225}−{c}^{\mathrm{2}} }\:\right)^{\mathrm{2}} \:\:\:{from}\:\mathrm{3}^{{rd}} \\ $$$$\Rightarrow\:\: \\ $$$$\:\mathrm{2}{c}\sqrt{\mathrm{196}−{c}^{\mathrm{2}} }−\mathrm{27}\:\:=\:\left({c}+\sqrt{\mathrm{225}−{c}^{\mathrm{2}} }\:\right)^{\mathrm{2}} \\ $$$$\:\:…… \\ $$