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Question-88943




Question Number 88943 by jagoll last updated on 14/Apr/20
Commented by john santu last updated on 14/Apr/20
1) 20+22−39 = 3  ⇒3^(4−1)  = 3^3  = 27  2)7+7−13 = 1  ⇒ 1^(3−1)  = x^2  ⇒ x = 1
$$\left.\mathrm{1}\right)\:\mathrm{20}+\mathrm{22}−\mathrm{39}\:=\:\mathrm{3} \\ $$$$\Rightarrow\mathrm{3}^{\mathrm{4}−\mathrm{1}} \:=\:\mathrm{3}^{\mathrm{3}} \:=\:\mathrm{27} \\ $$$$\left.\mathrm{2}\right)\mathrm{7}+\mathrm{7}−\mathrm{13}\:=\:\mathrm{1} \\ $$$$\Rightarrow\:\mathrm{1}^{\mathrm{3}−\mathrm{1}} \:=\:{x}^{\mathrm{2}} \:\Rightarrow\:{x}\:=\:\mathrm{1} \\ $$
Commented by jagoll last updated on 14/Apr/20
thanks sir
$${thanks}\:{sir} \\ $$

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