Question Number 89007 by naka3546 last updated on 14/Apr/20
Answered by TANMAY PANACEA. last updated on 14/Apr/20
$$\frac{{a}^{\mathrm{2}} }{{b}+{c}+{d}}+{a} \\ $$$$\frac{{a}^{\mathrm{2}} +{ab}+{ac}+{ad}}{{b}+{c}+{d}} \\ $$$$\frac{{a}\left({a}+{b}+{c}+{d}\right)}{{b}+{c}+{d}} \\ $$$${thus}\:{given}\:{expression} \\ $$$$\left({a}+{b}+{c}+{d}\right)\left(\frac{{a}}{{b}+{c}+{d}}+\frac{{b}}{{c}+{d}+{a}}+\frac{{c}}{{a}+{b}+{d}}+\frac{{d}}{{a}+{b}+{c}}\right)−\left({a}+{b}+{c}+{d}\right) \\ $$$$\left({a}+{b}+{c}+{d}\right)×\mathrm{1}−\left({a}+{b}+{c}+{d}\right) \\ $$$$=\mathrm{0} \\ $$
Commented by $@ty@m123 last updated on 14/Apr/20
$${Nice}!!! \\ $$
Commented by TANMAY PANACEA. last updated on 14/Apr/20
$${most}\:{eelcome}\:{sir} \\ $$