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Question-89007




Question Number 89007 by naka3546 last updated on 14/Apr/20
Answered by TANMAY PANACEA. last updated on 14/Apr/20
(a^2 /(b+c+d))+a  ((a^2 +ab+ac+ad)/(b+c+d))  ((a(a+b+c+d))/(b+c+d))  thus given expression  (a+b+c+d)((a/(b+c+d))+(b/(c+d+a))+(c/(a+b+d))+(d/(a+b+c)))−(a+b+c+d)  (a+b+c+d)×1−(a+b+c+d)  =0
$$\frac{{a}^{\mathrm{2}} }{{b}+{c}+{d}}+{a} \\ $$$$\frac{{a}^{\mathrm{2}} +{ab}+{ac}+{ad}}{{b}+{c}+{d}} \\ $$$$\frac{{a}\left({a}+{b}+{c}+{d}\right)}{{b}+{c}+{d}} \\ $$$${thus}\:{given}\:{expression} \\ $$$$\left({a}+{b}+{c}+{d}\right)\left(\frac{{a}}{{b}+{c}+{d}}+\frac{{b}}{{c}+{d}+{a}}+\frac{{c}}{{a}+{b}+{d}}+\frac{{d}}{{a}+{b}+{c}}\right)−\left({a}+{b}+{c}+{d}\right) \\ $$$$\left({a}+{b}+{c}+{d}\right)×\mathrm{1}−\left({a}+{b}+{c}+{d}\right) \\ $$$$=\mathrm{0} \\ $$
Commented by $@ty@m123 last updated on 14/Apr/20
Nice!!!
$${Nice}!!! \\ $$
Commented by TANMAY PANACEA. last updated on 14/Apr/20
most eelcome sir
$${most}\:{eelcome}\:{sir} \\ $$

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