Question-89172

Question Number 89172 by M±th+et£s last updated on 15/Apr/20

Answered by mahdi last updated on 15/Apr/20

{(\frac{x^{1} . x^{\frac{- b}{a}} . x^{\frac{1}{a}} . x^{\frac{b}{a^{2}}}}{x^{\frac{b}{a^{2}}} . x^{\frac{a}{a}}})}^{\frac{1}{b - 1}} = {(x^{\frac{1 - b}{a}})}^{\frac{1}{b - 1}} = x^{\frac{- 1}{a}} = \frac{1}{\sqrt[a]{x}}

Commented by M±th+et£s last updated on 15/Apr/20

p e r f e c t . t h a n k y o u s i r