Question Number 89172 by M±th+et£s last updated on 15/Apr/20
Answered by mahdi last updated on 15/Apr/20
$$\left(\frac{\mathrm{x}^{\mathrm{1}} .\mathrm{x}^{\frac{−\mathrm{b}}{\mathrm{a}}} .\mathrm{x}^{\frac{\mathrm{1}}{\mathrm{a}}} .\mathrm{x}^{\frac{\mathrm{b}}{\mathrm{a}^{\mathrm{2}} }} }{\mathrm{x}^{\frac{\mathrm{b}}{\mathrm{a}^{\mathrm{2}} }} .\mathrm{x}^{\frac{\mathrm{a}}{\mathrm{a}}} }\right)^{\frac{\mathrm{1}}{\mathrm{b}−\mathrm{1}}} =\left(\mathrm{x}^{\frac{\mathrm{1}−\mathrm{b}}{\mathrm{a}}} \right)^{\frac{\mathrm{1}}{\mathrm{b}−\mathrm{1}}} =\mathrm{x}^{\frac{−\mathrm{1}}{\mathrm{a}}} =\frac{\mathrm{1}}{\:\sqrt[{\mathrm{a}}]{\mathrm{x}}} \\ $$
Commented by M±th+et£s last updated on 15/Apr/20
$${perfect}.\:{thank}\:{you}\:{sir} \\ $$