Question-89647

Question Number 89647 by otchereabdullai@gmail.com last updated on 18/Apr/20

Answered by mahdi last updated on 18/Apr/20

\frac{sinx}{AC} = \frac{\sin (120 - x)}{AO}

\frac{\sin 10}{AO} = \frac{\sin 150}{AB}

\Rightarrow \frac{sinx}{AC} = \frac{\sin (120 - x)}{AB \frac{\sin 10}{\sin 150}} \overset{AC = AB}{\Rightarrow}

\frac{sinx}{\sin (120 - x)} = \frac{\sin 150}{\sin 10} \Rightarrow x = 100

Commented by jagoll last updated on 18/Apr/20

i {don}^{'} t see the AO line on the

matter sir ?

Commented by mahdi last updated on 18/Apr/20

i sorry jagoll, {point}^{″} O^{″} is center of Δ .

or C \hat{O A} = \hat{x}

Commented by jagoll last updated on 18/Apr/20

thank you

Commented by otchereabdullai@gmail.com last updated on 18/Apr/20

thank you sir