Question Number 89749 by cindiaulia last updated on 19/Apr/20
Commented by mr W last updated on 19/Apr/20
Commented by mr W last updated on 19/Apr/20
![∫_(−8) ^0 (8−(−x))dx+∫_0 ^( 8) (8−x)dx =2∫_0 ^( 8) (8−x)dx =[16x−x^2 ]_0 ^8 =16×8−8^2 =64](https://www.tinkutara.com/question/Q89758.png)
$$\int_{−\mathrm{8}} ^{\mathrm{0}} \left(\mathrm{8}−\left(−{x}\right)\right){dx}+\int_{\mathrm{0}} ^{\:\mathrm{8}} \left(\mathrm{8}−{x}\right){dx} \\ $$$$=\mathrm{2}\int_{\mathrm{0}} ^{\:\mathrm{8}} \left(\mathrm{8}−{x}\right){dx} \\ $$$$=\left[\mathrm{16}{x}−{x}^{\mathrm{2}} \right]_{\mathrm{0}} ^{\mathrm{8}} \\ $$$$=\mathrm{16}×\mathrm{8}−\mathrm{8}^{\mathrm{2}} \\ $$$$=\mathrm{64} \\ $$
Commented by jagoll last updated on 19/Apr/20
$$\mathrm{hahaha} \\ $$
Commented by mr W last updated on 19/Apr/20
$${dear}\:{sir}: \\ $$$${your}\:{posts}\:{disturb}\:{very}\:{much}! \\ $$$${so}\:{please}: \\ $$$$\left(\mathrm{1}\right)\:{don}'{t}\:{post}\:{the}\:{same}\:{question}\:{more} \\ $$$${than}\:{one}\:{time}! \\ $$$$\left(\mathrm{2}\right)\:{crop}\:{your}\:{picture}\:{before}\:{posting}! \\ $$$${like}\:{this}: \\ $$