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Question-90160




Question Number 90160 by A8;15: last updated on 21/Apr/20
Answered by TANMAY PANACEA. last updated on 21/Apr/20
put x=1 in RHS  (√(61+6−3)) =8  put x=1 LHS  16^(((1/( (√2) )))^2 ) +16^(((1/( (√2))))^2 )   (4^2 )^(1/2) +(4^2 )^(1/2) =8  trial and error
$${put}\:{x}=\mathrm{1}\:{in}\:{RHS} \\ $$$$\sqrt{\mathrm{61}+\mathrm{6}−\mathrm{3}}\:=\mathrm{8} \\ $$$${put}\:{x}=\mathrm{1}\:{LHS} \\ $$$$\mathrm{16}^{\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}\:}\right)^{\mathrm{2}} } +\mathrm{16}^{\left(\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}\right)^{\mathrm{2}} } \\ $$$$\left(\mathrm{4}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} +\left(\mathrm{4}^{\mathrm{2}} \right)^{\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{8} \\ $$$${trial}\:{and}\:{error} \\ $$

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