Question Number 90168 by M±th+et£s last updated on 21/Apr/20
Commented by TANMAY PANACEA. last updated on 21/Apr/20
$${i}\:{think}\:{option}\:{A}\:{for}\:\left({II}\right) \\ $$
Commented by M±th+et£s last updated on 21/Apr/20
$${how}\:{did}\:{you}\:{get}\:{A}\:{sir} \\ $$
Commented by TANMAY PANACEA. last updated on 21/Apr/20
$${ok}\:{let}\:{me}\:{recheck} \\ $$
Commented by M±th+et£s last updated on 21/Apr/20
$${thank}\:{you}\:{sir} \\ $$
Answered by TANMAY PANACEA. last updated on 21/Apr/20
$${z}_{\mathrm{1}} −{z}_{\mathrm{2}} \\ $$$$=\mathrm{2}+{i}−\mathrm{1}−\mathrm{3}{i} \\ $$$$=\mathrm{1}−\mathrm{2}{i} \\ $$$${iIm} \\ $$$$={i}\left(−\mathrm{2}\right)=−\mathrm{2}{i} \\ $$
Commented by M±th+et£s last updated on 21/Apr/20
$${thank}\:{you} \\ $$