Question Number 90706 by I want to learn more last updated on 25/Apr/20
Commented by jagoll last updated on 25/Apr/20
$${t}\:=\:\sqrt{\mathrm{4}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} }\:=\:\mathrm{5} \\ $$$${x}\:=\:\sqrt{\mathrm{5}^{\mathrm{2}} −\mathrm{3}^{\mathrm{2}} }=\:\mathrm{4} \\ $$$$ \\ $$
Answered by mr W last updated on 25/Apr/20
Commented by jagoll last updated on 25/Apr/20
$${AC}\:=\:\mathrm{4}.\:{AB}\:=\:\mathrm{5} \\ $$$${then}\:{x}\:=\:\mathrm{4} \\ $$
Commented by jagoll last updated on 25/Apr/20
$${yeah}…{my}\:{answer}\:{is}\:{correct} \\ $$
Commented by I want to learn more last updated on 25/Apr/20
$$\mathrm{Thanks}\:\mathrm{sir} \\ $$
Answered by I want to learn more last updated on 25/Apr/20
$$\mathrm{Thanks}\:\mathrm{sir}. \\ $$