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Question-91714




Question Number 91714 by jagoll last updated on 02/May/20
Commented by Tony Lin last updated on 02/May/20
∫_0 ^2 (ln3^((2π)/3) )e^x^2  dx  =(ln3^((2π)/3) )∫_0 ^2 e^x^2  dx  =(ln3^((2π)/3) )((√π)/2)[erfi(2)−erf(0)]  =(ln3^((2π)/3) )((√π)/2)erfi(2)  ≈37.8563
02(ln32π3)ex2dx=(ln32π3)02ex2dx=(ln32π3)π2[erfi(2)erf(0)]=(ln32π3)π2erfi(2)37.8563

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