Question-91714 Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 91714 by jagoll last updated on 02/May/20 Commented by Tony Lin last updated on 02/May/20 ∫02(ln32π3)ex2dx=(ln32π3)∫02ex2dx=(ln32π3)π2[erfi(2)−erf(0)]=(ln32π3)π2erfi(2)≈37.8563 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: For-an-axis-passing-through-the-centre-of-mass-of-a-rectangular-plate-along-its-length-Show-that-its-moment-of-inertia-is-ML-2-12-and-the-radius-of-gyration-is-L-2-3-Next Next post: Solve-for-real-numbers-1-sin-2k-x-1-cos-2k-x-8-k-Z- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.