Question-91844

Question Number 91844 by Power last updated on 03/May/20

Commented by mr W last updated on 03/May/20

y o u a r e b a c k! t h e s a m e q u e s t i o n s s e e m

t o b e b a c k t o o \dots

Commented by mr W last updated on 03/May/20

\int_{0}^{1000} ⌊ x ⌋ d x

= \underset{n = 0}{\sum^{999}} \int_{n}^{n + 1} ⌊ x ⌋ d x

= \underset{n = 0}{\sum^{999}} {n \int_{n}^{n + 1} d x}

= \underset{n = 0}{\sum^{999}} n

= \frac{999 \times 1000}{2}

= 499500

Commented by Power last updated on 03/May/20

yes sir

Commented by Power last updated on 03/May/20

thank you

Commented by john santu last updated on 03/May/20

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