Question-92214

Question Number 92214 by hovero clinton last updated on 05/May/20

Commented by mathmax by abdo last updated on 05/May/20

f o r x \to 0^{+} w e s e e \frac{1}{l n x} < 0 s o w e c a n t u s e e x p o \dots! p e r h a p s t h e

Q i s g i n d {l i m}_{x \to 0^{+}} {(- \frac{1}{l n x})}^{\frac{1}{l n (e^{x} - 1)}} \dots .