Question-92608

Question Number 92608 by jagoll last updated on 08/May/20

Commented by john santu last updated on 08/May/20

g (t) = {\begin{cases} - \frac{1}{2} t, - 4 ⩽ t ⩽ 0 \\ - \sqrt{9 - {(t - 3)}^{2}}, 0 ⩽ t ⩽ 6 \\ 3, 6 < t ⩽ 8 \end{cases}

f (x) = 3 x + \underset{0}{\int^{x}} g (t) dt

f (x) = 3 x + {\begin{cases} - \frac{1}{4} x^{2} \\ - \frac{9}{2} \sin^{- 1} (\frac{x - 3}{3}) - \frac{1}{2} (\frac{x - 3}{3}) \sqrt{6 x - x^{2}} + \frac{9 π}{4} \\ 6 x \end{cases}

Commented by jagoll last updated on 08/May/20

find f (x) = 3 x + \underset{0}{\int^{x}} g (t) dt

graph g (x) it shown above

Commented by MJS last updated on 08/May/20

\int_{t} \dots d t is not possible

Commented by jagoll last updated on 08/May/20

why sir ?

f (x) = 3 x + \int_{0}^{x} g (t) dt sir

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