Question Number 93540 by M±th+et+s last updated on 13/May/20
Commented by M±th+et+s last updated on 13/May/20
$${correct}\:{sir}\: \\ $$
Commented by M±th+et+s last updated on 13/May/20
$${The}\:{digonal}\:{BD}\:{of}\:{the}\:{square}\:{ABCD} \\ $$$${cuts}\:{the}\:\mathrm{45}°−{triangle}\:{into}\:\mathrm{2}\:{parts}. \\ $$$${Area}\:{of}\:{red}\::\:{Area}\:{of}\:{blue}=? \\ $$
Commented by Shakhzod last updated on 13/May/20
$${What}\:{should}\:{we}\:{do}\:{it}? \\ $$
Commented by M±th+et+s last updated on 13/May/20
$${find}\:{the}\:{ratio}\:{of}\:{two}\:{parts} \\ $$
Commented by mr W last updated on 13/May/20
$${without}\:{calculation}: \\ $$$$\frac{{red}}{{blue}}=\mathrm{1} \\ $$
Commented by Ari last updated on 13/May/20
$$\mathrm{why}\:\mathrm{can}\:\mathrm{samone}\:\mathrm{explayn}\:\mathrm{this}? \\ $$
Commented by mr W last updated on 14/May/20
$${just}\:{look}\:{at}\:{the}\:{situation}\:{when}\:{the}\: \\ $$$${red}+{blue}\:{areas}\:{form}\:{the}\:{triangle} \\ $$$$\Delta{ABC}. \\ $$