Question Number 94706 by i jagooll last updated on 20/May/20
Answered by john santu last updated on 20/May/20
$${x}\:=\:\mathrm{42}\:{m}^{\mathrm{2}} \\ $$
Commented by i jagooll last updated on 20/May/20
$$\mathrm{explain}\:\mathrm{sir} \\ $$
Commented by john santu last updated on 21/May/20
Commented by john santu last updated on 21/May/20
$${x}\:=\:{a}\:+\:\mathrm{42}−{a}\:=\:\mathrm{42}\:\mathrm{m}^{\mathrm{2}} \\ $$
Commented by i jagooll last updated on 21/May/20
$$\mathrm{thank}\:\mathrm{you} \\ $$
Answered by mr W last updated on 20/May/20
Commented by mr W last updated on 20/May/20
$${S}={area}\:{of}\:{square} \\ $$$${A}_{\mathrm{1}} +{C}_{\mathrm{1}} =\frac{{S}}{\mathrm{4}} \\ $$$${A}_{\mathrm{2}} +{C}_{\mathrm{2}} =\frac{{S}}{\mathrm{4}} \\ $$$$\Rightarrow{A}_{\mathrm{1}} +{A}_{\mathrm{2}} +{C}_{\mathrm{1}} +{C}_{\mathrm{2}} =\frac{{S}}{\mathrm{2}} \\ $$$$\Rightarrow{A}+{C}=\frac{{S}}{\mathrm{2}} \\ $$$${similarly} \\ $$$$\Rightarrow{B}_{\mathrm{1}} +{B}_{\mathrm{2}} +{D}_{\mathrm{1}} +{D}_{\mathrm{2}} =\frac{{S}}{\mathrm{2}} \\ $$$$\Rightarrow{B}+{D}=\frac{{S}}{\mathrm{2}} \\ $$$$\Rightarrow{A}+{C}={B}+{D} \\ $$$$\Rightarrow\mathrm{24}+\mathrm{48}=\mathrm{30}+{x} \\ $$$$\Rightarrow{x}=\mathrm{42} \\ $$
Commented by i jagooll last updated on 21/May/20
$$\mathrm{thank}\:\mathrm{you}\:\mathrm{sir} \\ $$