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Question-96437




Question Number 96437 by bemath last updated on 01/Jun/20
Answered by bobhans last updated on 01/Jun/20
xy−3x+5y−15 = −15  (x+5)(y−3) = −15  (1) x+5 = ±1; y−3 = ∓15  (2)x+5 = ± 3 ; y−3 = ∓ 5   (3) x+5 = ±5 ; y−3 = ∓ 3  (4) x+5 = ±15 ; y−3 = ∓ 1
$$\boldsymbol{{xy}}−\mathrm{3}\boldsymbol{{x}}+\mathrm{5}\boldsymbol{{y}}−\mathrm{15}\:=\:−\mathrm{15} \\ $$$$\left(\boldsymbol{{x}}+\mathrm{5}\right)\left(\boldsymbol{{y}}−\mathrm{3}\right)\:=\:−\mathrm{15} \\ $$$$\left(\mathrm{1}\right)\:\boldsymbol{{x}}+\mathrm{5}\:=\:\pm\mathrm{1};\:\mathrm{y}−\mathrm{3}\:=\:\mp\mathrm{15} \\ $$$$\left(\mathrm{2}\right){x}+\mathrm{5}\:=\:\pm\:\mathrm{3}\:;\:\mathrm{y}−\mathrm{3}\:=\:\mp\:\mathrm{5}\: \\ $$$$\left(\mathrm{3}\right)\:{x}+\mathrm{5}\:=\:\pm\mathrm{5}\:;\:\mathrm{y}−\mathrm{3}\:=\:\mp\:\mathrm{3} \\ $$$$\left(\mathrm{4}\right)\:{x}+\mathrm{5}\:=\:\pm\mathrm{15}\:;\:\mathrm{y}−\mathrm{3}\:=\:\mp\:\mathrm{1} \\ $$
Commented by bemath last updated on 01/Jun/20
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