Question Number 96543 by Hamida last updated on 02/Jun/20
Answered by mathmax by abdo last updated on 02/Jun/20
$$\mathrm{y}^{'} \:=\mathrm{4x}^{\mathrm{3}} \mathrm{sin}\left(\mathrm{6x}\right)\:+\mathrm{6x}^{\mathrm{4}} \:\mathrm{cos}\left(\mathrm{6x}\right)\:+\mathrm{6cos}\left(\mathrm{18x}\right)−\mathrm{18}×\mathrm{6x}\:\mathrm{sin}\left(\mathrm{18x}\right) \\ $$