Question Number 96606 by Hamida last updated on 03/Jun/20
Commented by Tony Lin last updated on 03/Jun/20
$${y}'=\frac{\mathrm{5}}{\mathrm{13}}{e}^{\frac{\mathrm{5}}{\mathrm{13}}{x}} +\mathrm{13}{sec}\left(\mathrm{13}{x}\right){tan}\left(\mathrm{13}{x}\right) \\ $$