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Question-97130




Question Number 97130 by Quadri last updated on 06/Jun/20
Answered by Sourav mridha last updated on 06/Jun/20
=(1/(2ln(2)))∫((d(1+2^x^2  ))/((1+2^x^2  )))=(1/(ln(4))).ln(1+2^x^2  )+c
$$=\frac{\mathrm{1}}{\mathrm{2}\boldsymbol{{ln}}\left(\mathrm{2}\right)}\int\frac{\boldsymbol{{d}}\left(\mathrm{1}+\mathrm{2}^{\boldsymbol{{x}}^{\mathrm{2}} } \right)}{\left(\mathrm{1}+\mathrm{2}^{\boldsymbol{{x}}^{\mathrm{2}} } \right)}=\frac{\mathrm{1}}{\boldsymbol{{ln}}\left(\mathrm{4}\right)}.\boldsymbol{{ln}}\left(\mathrm{1}+\mathrm{2}^{\boldsymbol{{x}}^{\mathrm{2}} } \right)+\boldsymbol{{c}} \\ $$

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