Question-97305

Question Number 97305 by eidmarie last updated on 07/Jun/20

Answered by MJS last updated on 07/Jun/20

crazy question the value of the integral is −6+((97(√(11)))/(55))arctan ((√(11))/3) +(1/(10))(9ln 5 −28ln 2) ⇒ a=−6+((97(√(11)))/(55))arctan ((√(11))/3) b=2^(−14/5) 5^(9/10)

$$\mathrm{crazy}\:\mathrm{question} \\ $$$$\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{integral}\:\mathrm{is} \\ $$$$−\mathrm{6}+\frac{\mathrm{97}\sqrt{\mathrm{11}}}{\mathrm{55}}\mathrm{arctan}\:\frac{\sqrt{\mathrm{11}}}{\mathrm{3}}\:+\frac{\mathrm{1}}{\mathrm{10}}\left(\mathrm{9ln}\:\mathrm{5}\:−\mathrm{28ln}\:\mathrm{2}\right) \\ $$$$\Rightarrow \\ $$$${a}=−\mathrm{6}+\frac{\mathrm{97}\sqrt{\mathrm{11}}}{\mathrm{55}}\mathrm{arctan}\:\frac{\sqrt{\mathrm{11}}}{\mathrm{3}} \\ $$$${b}=\mathrm{2}^{−\mathrm{14}/\mathrm{5}} \mathrm{5}^{\mathrm{9}/\mathrm{10}} \\ $$

Commented by bobhans last updated on 07/Jun/20