Question Number 97355 by bagjamath last updated on 07/Jun/20
Commented by PRITHWISH SEN 2 last updated on 07/Jun/20
$$=\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\:\left(\frac{\pi}{\mathrm{n}+\mathrm{1}}+\frac{\pi}{\mathrm{n}+\mathrm{1}}+……+\frac{\pi}{\mathrm{n}+\mathrm{1}}\:\mathrm{ntimes}\:\right) \\ $$$$=\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\:\frac{\pi}{\mathrm{1}+\frac{\mathrm{1}}{\mathrm{n}}}\:=\:\pi \\ $$