Question Number 97401 by M±th+et+s last updated on 07/Jun/20
Commented by M±th+et+s last updated on 07/Jun/20
$$\mathrm{1}{F}\mathrm{1}\:{is}\:{the}\:{kummer}\:{confluent}\:{hypergeometric} \\ $$$${function} \\ $$$${U}\left({a},{b},{x}\right)\:{the}\:{confluent}\:{hypergeometric} \\ $$$${function}\:{of}\:{the}\:{second}\:{kind} \\ $$