Question-98275

Question Number 98275 by liki last updated on 12/Jun/20

Commented by liki last updated on 12/Jun/20

$$…..\:\mathrm{please}\:\mathrm{help}\:\mathrm{me} \\ $$

Answered by mr W last updated on 12/Jun/20

say P(x,y) ⇒A(2x,0) ⇒B(0,2y) (1/2)×2x×2y=8 ⇒xy=4 ⇒y=(4/x)

$${say}\:{P}\left({x},{y}\right) \\ $$$$\Rightarrow{A}\left(\mathrm{2}{x},\mathrm{0}\right) \\ $$$$\Rightarrow{B}\left(\mathrm{0},\mathrm{2}{y}\right) \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{2}{x}×\mathrm{2}{y}=\mathrm{8} \\ $$$$\Rightarrow{xy}=\mathrm{4} \\ $$$$\Rightarrow{y}=\frac{\mathrm{4}}{{x}} \\ $$

Commented by liki last updated on 12/Jun/20

.. sory sir i didn′t understand 2x and 2y

$$..\:\boldsymbol{\mathrm{sory}}\:\boldsymbol{\mathrm{sir}}\:\boldsymbol{\mathrm{i}}\:\boldsymbol{\mathrm{didn}}'\boldsymbol{\mathrm{t}}\:\:\boldsymbol{\mathrm{understand}}\:\:\mathrm{2}\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{and}}\:\mathrm{2}\boldsymbol{\mathrm{y}}\: \\ $$

Commented by mr W last updated on 12/Jun/20

P (x,y) is midpoint of AB. x_P =((x_A +x_B )/2) x_B =0, x_P =x ⇒x_A =2x similarly ⇒y_B =2y

$${P}\:\left({x},{y}\right)\:{is}\:{midpoint}\:{of}\:{AB}. \\ $$$${x}_{{P}} =\frac{{x}_{{A}} +{x}_{{B}} }{\mathrm{2}} \\ $$$${x}_{{B}} =\mathrm{0},\:{x}_{{P}} ={x} \\ $$$$\Rightarrow{x}_{{A}} =\mathrm{2}{x} \\ $$$${similarly} \\ $$$$\Rightarrow{y}_{{B}} =\mathrm{2}{y} \\ $$

Commented by mr W last updated on 12/Jun/20

Commented by Aziztisffola last updated on 13/Jun/20

Hi sir, we can draw with this application like this?

$$\mathrm{Hi}\:\mathrm{sir},\:\mathrm{we}\:\mathrm{can}\:\mathrm{draw}\:\mathrm{with}\:\mathrm{this}\:\mathrm{application}\:\mathrm{like}\:\mathrm{this}? \\ $$

Commented by mr W last updated on 13/Jun/20

$${we}\:{can}'{t}\:{draw}\:{with}\:{this}\:{app}.\:{but}\:{we} \\ $$$${can}\:{draw}\:{with}\:{any}\:{other}\:{apps}\:{and}\:{then} \\ $$$${input}\:{the}\:{images}\:{into}\:{this}\:{app}. \\ $$

Commented by Aziztisffola last updated on 13/Jun/20