Question-99194

Question Number 99194 by bemath last updated on 19/Jun/20

Answered by bramlex last updated on 19/Jun/20

s u p p o s e p r o b a b i l i t y w i n o r d r a w o r l o s e a r e

s a m e i s \frac{1}{3}

n o t t o l o s e i n t h o s e t h r e e m a t c h e s

c a s e (1) (3 w) \Rightarrow {(\frac{1}{3})}^{3} = \frac{1}{27}

c a s e (2) (2 w, 1 d) \Rightarrow C (3, 2) {(\frac{1}{3})}^{3} = \frac{1}{9}

c a s e (3) (1 w, 2 d) \Rightarrow C (3, 1) {(\frac{1}{3})}^{3} = \frac{1}{9}

c a s e (4) (3 d) \Rightarrow {(\frac{1}{3})}^{3} = \frac{1}{27}

n o w p = 2 \times (\frac{1}{27} + \frac{1}{9}) = \frac{8}{27}

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