Question-99972

Question Number 99972 by bobhans last updated on 24/Jun/20

Commented by bemath last updated on 24/Jun/20

b = 9 \Rightarrow \lim_{x \to 0} \frac{a}{2 \sqrt{ax + 9}} = \frac{1}{3}; \frac{a}{6} = \frac{1}{3}

a = 2 . \Rightarrow \lim_{x \to 1} \frac{\sqrt{9 x - 4} - \sqrt{5}}{x - 1} = \frac{9}{2 \sqrt{5}}

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