Question-x-3-x-3-A-x-9-B-x-6-C-x-3-D-1-Give-a-reason-for-your-answer-

Question Number 38515 by Rio Mike last updated on 26/Jun/18

Q u e s t i o n;

x^{3} + x^{3} =

A) x^{9}

B) x^{6}

C) x^{3}

D) 1

G i v e a r e a s o n f o r y o u r a n s w e r .

Answered by MJS last updated on 26/Jun/18

x^{3} + x^{3} = x^{9} \Rightarrow 2 x^{3} = x^{9} \Rightarrow x = 0 \lor x^{6} = 2 \Rightarrow

\Rightarrow x = 0 \lor x = \pm \sqrt[6]{2} \lor x = - \frac{\sqrt[6]{2}}{2} \pm i \frac{\sqrt[6]{2}}{2} \sqrt{3} \lor x = \frac{\sqrt[6]{2}}{2} \pm i \frac{\sqrt[6]{2}}{2} \sqrt{3}

x^{3} + x^{3} = x^{6} \Rightarrow 2 x^{3} = x^{6} \Rightarrow x = 0 \lor x^{3} = 2 \Rightarrow

\Rightarrow x = 0 \lor x = \sqrt[3]{2} \lor x = - \frac{\sqrt[3]{2}}{2} \pm i \frac{\sqrt[3]{2}}{2} \sqrt{3}

x^{3} + x^{3} = x^{3} \Rightarrow x^{3} = 0 \Rightarrow x = 0

x^{3} + x^{3} = 1 \Rightarrow x^{3} = \frac{1}{2} \Rightarrow x = \frac{\sqrt[3]{4}}{2} \lor x = - \frac{\sqrt[3]{4}}{4} \pm i \frac{\sqrt[3]{4}}{4} \sqrt{3}

Facebook Tweet Pin