R-1-cos-0-5-Rsin-4-R-

Question Number 57700 by Nameed last updated on 10/Apr/19

R (1 - \cos θ) = 0.5

Rsin θ = 4

R = ?

θ = ?

Answered by tanmay.chaudhury50@gmail.com last updated on 10/Apr/19

R \times 2 s i n \frac{θ}{2} c o s \frac{θ}{2} = 4

R (2 {s i n}^{2} \frac{θ}{2}) = \frac{1}{2}

\frac{2 {R s i n}^{2} \frac{θ}{2}}{2 R s i n \frac{θ}{2} c o s \frac{θ}{2}} = \frac{1}{2 \times 4}

t a n \frac{θ}{2} = \frac{1}{8} \to θ = 2 {t a n}^{- 1} (\frac{1}{8})

s i n \frac{θ}{2} = \frac{1}{\sqrt{8^{2} + 1^{2}}} = \frac{1}{\sqrt{65}}

R \times 2 {s i n}^{2} \frac{θ}{2} = \frac{1}{2}

R \times 2 \times \frac{1}{65} = \frac{1}{2}

R = \frac{65}{4}

Commented by math1967 last updated on 10/Apr/19

t a n \frac{θ}{2} = \frac{1}{8} ∴ θ = {2 \tan}^{- 1} \frac{1}{8}

Commented by tanmay.chaudhury50@gmail.com last updated on 10/Apr/19

t h a n k y o u d a d a \dots v o t e a r k i k h a b a r \dots k o l k a t a t e

Commented by math1967 last updated on 11/Apr/19

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