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Range-of-function-f-x-6-x-3-x-6-x-3-x-2-




Question Number 31865 by rahul 19 last updated on 16/Mar/18
Range of function :  f(x)= 6^x +3^x +6^(−x) +3^(−x) +2.
Rangeoffunction:f(x)=6x+3x+6x+3x+2.
Commented by rahul 19 last updated on 16/Mar/18
my try :  f(x)= (6^(x/2) +6^((−x)/2) )^2 + (3^(x/2) +3^((−x)/2) )^2 −2≥6.  hence range is [−6,∞).
mytry:f(x)=(6x2+6x2)2+(3x2+3x2)226.hencerangeis[6,).
Commented by rahul 19 last updated on 16/Mar/18
but ans. given is [6,∞).
butans.givenis[6,).
Commented by Tinkutara last updated on 16/Mar/18
Apply AM-GM.
Commented by rahul 19 last updated on 16/Mar/18
plz tell where am i wrong ?
plztellwhereamiwrong?
Commented by Tinkutara last updated on 16/Mar/18
Because you assumed minimum  value of 6^(x/2) +6^((−x)/2)  to be 0 which is not.  6^(x/2) +6^((−x)/2)  has minimum value 2.
Becauseyouassumedminimumvalueof6x2+6x2tobe0whichisnot.6x2+6x2hasminimumvalue2.
Commented by rahul 19 last updated on 16/Mar/18
ok thanks !!
okthanks!!
Answered by mrW2 last updated on 16/Mar/18
f(x)=(6^x +6^(−x) )+(3^x +3^(−x) )+2  ≥2+2+2=6
f(x)=(6x+6x)+(3x+3x)+22+2+2=6
Commented by rahul 19 last updated on 16/Mar/18
yes sir, i have got the ans.  thank u sir!
yessir,ihavegottheans.thankusir!

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