Reduce-2n-1-3-5-2n-1-

Question Number 178486 by Acem last updated on 17/Oct/22

R e d u c e \frac{(2 n)!}{1 \times 3 \times 5 \times \dots \times (2 n - 1)}

Answered by Rasheed.Sindhi last updated on 17/Oct/22

R e d u c e \frac{(2 n)!}{1 \times 3 \times 5 \times \dots \times (2 n - 1)}

= \frac{1.2.3.4.5 \dots (2 n - 1) . 2 n}{1.3.5 \dots . . (2 n - 1)}

= 2.4.6 \dots . . 2 n

= 2^{n} (1.2.3 \dots . n)

= 2^{n} n!

Commented by Acem last updated on 17/Oct/22

G o o d S i r!

Commented by Acem last updated on 17/Oct/22

I t p r e f e r a t 2 n d l i n e p u t t t i n g t h e f o l l o w

= \frac{2 n . (2 n - 1) (2 n - 2) (2 n - 3) (2 n - 4) \dots . 6 \times 5 \times 4 \times 3 \times 2 \times 1}{1 \times 3 \times 5 \times \dots . \times (2 n - 1)}

= 2 n . (2 n - 2) (2 n - 4) . . 6 \times 4 \times 2

= 2^{n} . n (n - 1) (n - 2) \dots 3 \times 2 \times 1 = 2^{n} . n!

Commented by Rasheed.Sindhi last updated on 17/Oct/22

Ok sir, thank you!

Commented by Acem last updated on 17/Oct/22

T h e b e s t R a s h e e d, t h a n k y o u

Facebook Tweet Pin