Menu Close

Resolve-1-x-2-y-dx-x-2-y-x-3-dy-0-x-




Question Number 168909 by LEKOUMA last updated on 21/Apr/22
Resolve   (1−x^2 y)dx+(x^2 y−x^3 )dy=0 ; μ=μ(x)
$${Resolve}\: \\ $$$$\left(\mathrm{1}−{x}^{\mathrm{2}} {y}\right){dx}+\left({x}^{\mathrm{2}} {y}−{x}^{\mathrm{3}} \right){dy}=\mathrm{0}\:;\:\mu=\mu\left({x}\right) \\ $$
Commented by mr W last updated on 22/Apr/22
μ stands nowhere in the equation.
$$\mu\:{stands}\:{nowhere}\:{in}\:{the}\:{equation}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *