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resolve-x-3-x-6-1-into-partial-fraction-

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Question Number 34182 by NECx last updated on 02/May/18
resolve (x^3 /(x^6 −1)) into partial fraction
resolvex3x6−1intopartialfraction
Answered by math1967 last updated on 02/May/18
(1/2){(1/(x^3 +1)) +(1/(x^3 −1))}
12{1x3+1+1x3−1}
Answered by MJS last updated on 02/May/18
x^6 −1=(x−1)(x+1)(x^2 −x+1)(x^2 +x+1) (x^3 /(x^6 −1))=(1/6)((1/(x−1))+(1/(x+1))−((x−2)/(x^2 −x+1))−((x+2)/(x^2 +x+1)))
x6−1=(x−1)(x+1)(x2−x+1)(x2+x+1)x3x6−1=16(1x−1+1x+1−x−2x2−x+1−x+2x2+x+1)

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