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resolve-x-R-x-1-x-2-x-2-x-1-2-




Question Number 21251 by youssoufab last updated on 17/Sep/17
resolve :  ∀x∈R, (√(x+1))∣x−2∣=(√(x+2))∣x−1∣−2
$${resolve}\:: \\ $$$$\forall{x}\in\mathbb{R},\:\sqrt{{x}+\mathrm{1}}\mid{x}−\mathrm{2}\mid=\sqrt{{x}+\mathrm{2}}\mid{x}−\mathrm{1}\mid−\mathrm{2} \\ $$$$ \\ $$

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