Resoudre-dans-Z-a-b-z-a-b-z-N-3-a-b-

Question Number 184567 by a.lgnaoui last updated on 08/Jan/23

R e s o u d r e d a n s Z^{+}

\sqrt{a} + \sqrt{b} = z (a, b, z) \in N^{3}

a, b ?

Answered by Frix last updated on 08/Jan/23

a = n_{1}^{2} \land b = n_{2}^{2}

\Rightarrow

z = \sqrt{a} + \sqrt{b} = n_{1} + n_{2}

Commented by a.lgnaoui last updated on 08/Jan/23

n_{1} ? n_{2} ?

Commented by Frix last updated on 08/Jan/23

n_{1} \in N; n_{2} \in N

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