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Reupload-unanswered-question-sec-2-1-sec-2-2-sec-2-3-sec-2-89-




Question Number 165608 by naka3546 last updated on 05/Feb/22
Reupload  unanswered  question.  sec^2 1° + sec^2  2° + sec^2  3° + …+ sec^2  89°  =  ?
$$\mathrm{Reupload}\:\:\mathrm{unanswered}\:\:\mathrm{question}. \\ $$$$\mathrm{sec}^{\mathrm{2}} \mathrm{1}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{2}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{3}°\:+\:\ldots+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{89}°\:\:=\:\:? \\ $$

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