Question Number 118711 by Cristina last updated on 19/Oct/20
![Ripasso di matematica per la verifica L′addizione non gode della proprieta^ invariantiva 7+11=(7−3)+(11−3) FALSO Proprieta^ distributiva della moltiplicazione rispetto alla sottrazione 5•(6−4)=30−20 Risolvere la seguente espressione [(2+1)^4 •2^7 •3^3 ]:(6^(10) :6^8 )^3 −6=[3^4 •2^7 •3^3 ]:(6^2 )^3 −6=[3^7 •2^7 ]:6^6 −6= =6^7 :6^6 −6 Es. 184 pag.31 {[2+2•(5+4)•(8−5)]:(4•7)}^5 ={[2+2•9•3]:28}^5 ={[2+54]:28}^5 ={56:28}^5 = {2}^5 =2^5 =32](https://www.tinkutara.com/question/Q118711.png)
$$\mathrm{Ripasso}\:\mathrm{di}\:\mathrm{matematica}\:\mathrm{per}\:\mathrm{la}\:\mathrm{verifica} \\ $$$$\mathrm{L}'\mathrm{addizione}\:\mathrm{non}\:\mathrm{gode}\:\mathrm{della}\:\mathrm{propriet}\acute {\mathrm{a}}\:\mathrm{invariantiva} \\ $$$$\mathrm{7}+\mathrm{11}=\left(\mathrm{7}−\mathrm{3}\right)+\left(\mathrm{11}−\mathrm{3}\right)\:\:\:\:\mathrm{FALSO} \\ $$$$\mathrm{Propriet}\acute {\mathrm{a}}\:\mathrm{distributiva}\:\mathrm{della}\:\mathrm{moltiplicazione}\:\mathrm{rispetto}\:\mathrm{alla}\:\mathrm{sottrazione} \\ $$$$\mathrm{5}\bullet\left(\mathrm{6}−\mathrm{4}\right)=\mathrm{30}−\mathrm{20} \\ $$$$\mathrm{Risolvere}\:\mathrm{la}\:\mathrm{seguente}\:\mathrm{espressione} \\ $$$$\left[\left(\mathrm{2}+\mathrm{1}\right)^{\mathrm{4}} \bullet\mathrm{2}^{\mathrm{7}} \bullet\mathrm{3}^{\mathrm{3}} \right]:\left(\mathrm{6}^{\mathrm{10}} :\mathrm{6}^{\mathrm{8}} \right)^{\mathrm{3}} −\mathrm{6}=\left[\mathrm{3}^{\mathrm{4}} \bullet\mathrm{2}^{\mathrm{7}} \bullet\mathrm{3}^{\mathrm{3}} \right]:\left(\mathrm{6}^{\mathrm{2}} \right)^{\mathrm{3}} −\mathrm{6}=\left[\mathrm{3}^{\mathrm{7}} \bullet\mathrm{2}^{\mathrm{7}} \right]:\mathrm{6}^{\mathrm{6}} −\mathrm{6}= \\ $$$$=\mathrm{6}^{\mathrm{7}} :\mathrm{6}^{\mathrm{6}} −\mathrm{6} \\ $$$$\mathrm{Es}.\:\mathrm{184}\:\mathrm{pag}.\mathrm{31} \\ $$$$\left\{\left[\mathrm{2}+\mathrm{2}\bullet\left(\mathrm{5}+\mathrm{4}\right)\bullet\left(\mathrm{8}−\mathrm{5}\right)\right]:\left(\mathrm{4}\bullet\mathrm{7}\right)\right\}^{\mathrm{5}} =\left\{\left[\mathrm{2}+\mathrm{2}\bullet\mathrm{9}\bullet\mathrm{3}\right]:\mathrm{28}\right\}^{\mathrm{5}} =\left\{\left[\mathrm{2}+\mathrm{54}\right]:\mathrm{28}\right\}^{\mathrm{5}} =\left\{\mathrm{56}:\mathrm{28}\right\}^{\mathrm{5}} = \\ $$$$\left\{\mathrm{2}\right\}^{\mathrm{5}} =\mathrm{2}^{\mathrm{5}} =\mathrm{32} \\ $$
Commented by 1549442205PVT last updated on 19/Oct/20
$$\mathrm{Cristina},\mathrm{whatdo}\:\mathrm{you}\:\mathrm{want}\:\mathrm{to}\:\mathrm{query}\:\mathrm{to}\: \\ $$$$\mathrm{us}?\mathrm{If}\:\mathrm{can}\:\mathrm{you}\:\mathrm{should}\:\mathrm{try}\:\mathrm{to}\:\mathrm{speak}\:\mathrm{English} \\ $$