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S-n-4-1-n-2-6-1-n-find-n-1-S-n-and-n-1-S-n-




Question Number 47199 by Tawa1 last updated on 06/Nov/18
S_n   =  [4 − (1/(n^2  )) ,        6 + (1/n) ],   find           ∩_(n = 1) ^∞  S_n       and    ∪_(n = 1) ^∞   S_n
Sn=[41n2,6+1n],findn=1Snandn=1Sn

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