Question Number 183330 by Matica last updated on 25/Dec/22
$$\:\:{S}\:=\:{sinhx}+{sinh}^{\mathrm{2}} {x}\:+\:{sinh}^{\mathrm{3}} {x}+…+{sinh}^{{n}} {x}=? \\ $$
Commented by mokys last updated on 25/Dec/22
$${S}\:=\:\frac{{sinhx}}{\mathrm{1}−{sinhx}} \\ $$
Commented by Ar Brandon last updated on 25/Dec/22
Isn't this rather the sum to infinity?